# The equation of a line that passes through the point (1, 2) and the point 3 4 is

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Nicodemus1210
@Nicodemus1210

April 2019
1
948

The equation of the line that passes through the point 1,2 and the point 3,4

LouiseTantri2008

The equation of the line can be calculated by:
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-2)/(4-2)=(x-1)/(3-1)
(y-2)/2 = (x-1)/(2) => multiplied by cross
(y-2)×2 = (x-1)×2
2y-4 = 2x-2
2y= 2x-2+4
2y = 2x+2
y = x+1

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1. m=
m =
m =

2. mH1 =

mH1 =
mH1 =

mH2 =

mH2 = mH1.mH2 = -1So the two lines are perpendicular

3. m=

m=

4. m=

m=m = -3

5. m=

m= m = -2

6. m=

m= 7. PGL = y-y1 = m[x-x1]PGL = y-1 = 2[x-0]PGL = y-1 = 2xPGL = y = 2x+1

8. m=

m=
m=PGL = y-y1 = m[x-x1]

PGL = y+1 =

[x+1]PGL = 2[y+1] = x+1PGL = 2y+2 = x+1PGL = -x+2y+1 = 0

9. m=

m=m = 1PGL = y-y1 = m[x-x1]PGL = y-0 = 1[x+2]PGL = y = x+2

10. PGL =

PGL =
PGL = PGL = -4[y-2] = -6[x-1]PGL = -4y+8 = -6x+6

PGL = 6x-4y+2 = 0

The formula for the equation of a line that passes through two points. Substitute the points in the equation,

So, the equation of the line that passes through two points and one point is

So, the correct answer is D.

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