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Nicodemus1210

@Nicodemus1210

April 2019

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The equation of the line that passes through the point 1,2 and the point 3,4

LouiseTantri2008

###### Verified answer

The equation of the line can be calculated by:

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-2)/(4-2)=(x-1)/(3-1)

(y-2)/2 = (x-1)/(2) => multiplied by cross

(y-2)×2 = (x-1)×2

2y-4 = 2x-2

2y= 2x-2+4

2y = 2x+2

y = x+1

I hope this helps

23 votes

Thank you 51

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Answer posted by: handsome5953

1. m=

m =

m =

2. mH1 =

mH1 =

mH1 =

mH2 =

mH2 = mH1.mH2 = -1So the two lines are perpendicular

3. m=

m=

4. m=

m=m = -3

5. m=

m= m = -2

6. m=

m= 7. PGL = y-y1 = m[x-x1]PGL = y-1 = 2[x-0]PGL = y-1 = 2xPGL = y = 2x+1

8. m=

m=

m=PGL = y-y1 = m[x-x1]

PGL = y+1 =

[x+1]PGL = 2[y+1] = x+1PGL = 2y+2 = x+1PGL = -x+2y+1 = 0

9. m=

m=m = 1PGL = y-y1 = m[x-x1]PGL = y-0 = 1[x+2]PGL = y = x+2

10. PGL =

PGL =

PGL = PGL = -4[y-2] = -6[x-1]PGL = -4y+8 = -6x+6

PGL = 6x-4y+2 = 0

The formula for the equation of a line that passes through two points.

Substitute the points in the equation,

So, the equation of the line that passes through two points and one point is

**So, the correct answer is D.**

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